Write A Program To Check Leap Year In Java

Chapter: Date and Time Last Updated: 22-06-2023 14:07:27 UTC

Program:

            /* ............... START ............... */
                

import java.util.Scanner;

public class LeapYearChecker {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter a year: ");
        int year = scanner.nextInt();

        if (isLeapYear(year)) {
            System.out.println(year + " is a leap year.");
        } else {
            System.out.println(year + " is not a leap year.");
        }
    }

    public static boolean isLeapYear(int year) {
        // Leap year is divisible by 4 but not divisible by 100
        // unless it is divisible by 400
        if (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)) {
            return true;
        }
        return false;
    }
}

                /* ............... END ............... */
        

Output

Input: 2020
Output: 2020 is a leap year.

Input: 2021
Output: 2021 is not a leap year.

Input: 1900
Output: 1900 is not a leap year.

Input: 2000
Output: 2000 is a leap year.

Input: 2024
Output: 2024 is a leap year.

Notes:

• In this program, we use a Scanner to read input from the user. The isLeapYear method takes an integer year as input and returns true if it is a leap year, and false otherwise. The logic for checking leap year is as follows:
• A year is a leap year if it is divisible by 4.
• However, if the year is divisible by 100, it is not a leap year, unless it is divisible by 400.
• The isLeapYear method implements this logic and returns the result.
• In the main method, we prompt the user to enter a year, and then call the isLeapYear method to check whether it is a leap year or not. The program then prints the appropriate message based on the result.

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