Java Program To Calculate Time Difference In Seconds

Chapter: Date and Time Last Updated: 20-09-2023 14:48:20 UTC

Program:

            /* ............... START ............... */
                

import java.time.LocalDateTime;
import java.time.Duration;

public class TimeDifferenceInSeconds {
    public static void main(String[] args) {
        // Create two LocalDateTime objects representing two different times
        LocalDateTime startTime = LocalDateTime.of(2023, 9, 20, 10, 0, 0); // Replace with your start time
        LocalDateTime endTime = LocalDateTime.of(2023, 9, 20, 12, 30, 0); // Replace with your end time

        // Calculate the time difference in seconds
        Duration duration = Duration.between(startTime, endTime);
        long secondsDifference = duration.getSeconds();

        System.out.println("Time difference in seconds: " + secondsDifference + " seconds");
    }
}

                /* ............... END ............... */
        

Output

Time difference in seconds: 9000 seconds

In this example, the program calculates the time difference in seconds between
 the start time and end time, which is 2 hours and 30 minutes, or 9000 seconds.

Notes:

• First we create two LocalDateTime objects, startTime and endTime, representing the two different times for which we want to calculate the time difference.
• Then we use the Duration.between() method to calculate the duration between the two LocalDateTime objects. This method returns a Duration object.
• In next step we extract the number of seconds from the Duration object using the getSeconds() method and store it in the secondsDifference variable.
• Finally, we print the time difference in seconds.
• Replace the values of startTime and endTime with your desired date and time values to calculate the time difference between them in seconds.

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